An electron is to be released from rest on the central axis of a uniformly charged disk of radius R. The surface charge density on the disk is +4.00 μC/m^2 and ε0= 8.85 x 10^–12 F/m. What is the magnitude of the electron’s initial acceleration if released at distances of

a. R from the center of the disk?
b. R/100 from the center of the disk?
c. R/1000 from the center of the disk?
d. Why does the acceleration increase only slightly as the release point is moved closer to the disk?

Respuesta :

Answer:

[tex]a=11.86*10^1^5 m/s[/tex]

[tex]a=3.91864074*10^-^2^4 m/s^2[/tex]

[tex]a=3.95426275*10^-^2^4m/s^2[/tex]

Explanation:

From the question we are told that

The surface charge density on the disk is [tex]\sigma=+4.00 \mu C/m^2[/tex]

[tex]\varepsilon _0= 8.85 * 10^–12 F/m.[/tex]

a)Generally the electric field in this situation is given as  is mathematically given as

  [tex]E=\frac{\sigma}{\varepsilon_0} (1-\frac{R}{\sqrt{2}R}[/tex]

  [tex]E=\frac{\sigma}{\varepsilon_0} (1-\frac{1}{\sqrt{2}})[/tex]

  [tex]E=67.48*10^3 f/a[/tex]

Generally the Force of release of the electron  is mathematically given as

[tex]F=eE[/tex]

[tex]F=ma[/tex]

[tex]a*m=\frac{eE}{1}[/tex]

[tex]a=\frac{1.6*10^-^1^9 *67.48*10^3}{9.1*10^3^1}[/tex]

[tex]a=11.86*10^1^5 m/s[/tex]

b)Generally the electric field in R/100 from the center of the disk is given as  is mathematically given as

Generally

 [tex]E=\frac{\sigma}{\alpha \varepsilon_0}(1-\frac{1}{\sqrt{(100)^2} }[/tex]

 [tex]E=\frac{4.0*10^-^6}{2*8.854*10^-^1^2}(1-\frac{1}{\sqrt{(1+(100)^2} })[/tex]

 [tex]E=2.22872692*10^2^7[/tex]

Generally the Force of release of the electron  is mathematically given as

 [tex]a*m=\frac{eE}{1}[/tex]

 [tex]a=\frac{1.6*10^-^1^9 *2.22872692*10^2^7}{9.1*10^3^1}[/tex]

 [tex]a=3.91864074*10^-^2^4 m/s^2[/tex]

c)Generally the electric field in R/1000 from the center of the disk is given as  is mathematically given as

 [tex]E=\frac{\sigma}{\alpha \varepsilon_0}(1-\frac{1}{\sqrt{(1000)^2} }[/tex]

 [tex]E=\frac{4.0*10^-^6}{2*8.854*10^-^1^2}(1-\frac{1}{\sqrt{(1+(1000)^2} })[/tex]

[tex]E=2.24898694*10^2^7[/tex]

Generally the Force of release of the electron  is mathematically given as

 [tex]a*m=\frac{eE}{1}[/tex]

 [tex]a=\frac{1.6*10^-^1^9 *2.24898694*10^2^7}{9.1*10^3^1}[/tex]

 [tex]a=3.95426275*10^-^2^4m/s^2[/tex]

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