we know that
[tex] 4\frac{1}{3}= \frac{(4*3+1)}{3} =\frac{13}{3} [/tex]
[tex] 6\frac{1}{2}= \frac{(6*2+1)}{2}=\frac{13}{2} [/tex]
To find how long are [tex] 6\frac{1}{2} [/tex] sections placed end to end
Multiply the number of sections by the length of one section
so
[tex] \frac{13}{2} *\frac{13}{3} =\frac{169}{6}\ ft[/tex]
[tex] \frac{169}{6}\ ft =28\frac{1}{6}\ ft[/tex]
therefore
the answer is
[tex] 28\frac{1}{6} \ ft [/tex]