Answer:
The Potential Energy of the stretched spring is = 1.975 J
Explanation:
Recall that the potential energy of a spring of constant k stretched x\a distance x is given by the formula:
U = 1/2 k x^2
Therefore in our case, converting the stretch from cm of meters (0.05 m), this is
U = 1/2 * 79 * 0.05 J = 1.975 J
