Answer:
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FACTS TO KNOW BEFORE SOLVING :-
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According to the question ,
a) [tex]\sqrt{18} =\sqrt{9 \times 2} = \sqrt{9} \times \sqrt{2} = 3\sqrt{2}[/tex]
b) [tex]\sqrt{12} =\sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}[/tex]
c) [tex]\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}[/tex]