Question

The nth term of a sequence is 7(n + 2).
What are the first four terms?

Answer 1

Answer:

21, 28, 35, 42

Step-by-step explanation:

You need to do BODMAS / BIDMAS for this

So calculate what's inside the brackets first and then multiply by the 7

So

7(1+2) would be 7(3) which would be 7 x 3 = 21

and so on for the rest

7(2+2) = 28

7(3+2) = 35

7(4+2) = 42