Answer:
g(-2) = -19, g(0) = -5 and g(3) = -14
Step-by-step explanation:
The given function is :
[tex]g(x) = -2x^2 + 3x - 5[/tex] ...(1)
We need to find the function when x = -2,0 and 3.
Put x = -2 in equation (1).
[tex]g(-2) = -2(-2)^2 + 3(-2) - 5\\\\=-19[/tex]
Put x = 0 in equation (1).
[tex]g(0) = -2(0)^2 + 3(0) - 5\\\\=-5[/tex]
Put x = 3 in equation (1).
[tex]g(3) = -2(3)^2 + 3(3) - 5\\\\=-14[/tex]
Hence, g(-2) = -19, g(0) = -5 and g(3) = -14