Answer:
x = 8[tex]\sqrt{5}[/tex]
Step-by-step explanation:
Using the Altitude- on - Hypotenuse theorem
(leg of large Δ )² = (part of hypotenuse below it ) × (whole hypotenuse )
x² = 16 × (16 + 4) = 16 × 20 = 320 ( take square root of both sides )
x = [tex]\sqrt{320}[/tex] = [tex]\sqrt{64(5)}[/tex] = 8[tex]\sqrt{5}[/tex]
