Answer:
Use the given functions to establish and reduce u (4)
x=x2+1=x=1+i√32,1−i√32
w=x=1+i√32,1−i√32
u(4)=4u
Step-by-step explanation:
Answer:
5, probably
Step-by-step explanation:
you are looking for the function w(u(4)). you need to find u(x) first when x=4 so solve for u(4)=-x+2 so u(4)=-4+2=-2. now plug this -2 value into the function w(x) so w(-2)=-2^2+1 so basically =4+1 and I think that is probably 5 maybe the value of w(u(4))=5
