Question

The area of a newspaper page (opened up) is about 630.92 square inches. Determine the length and width of the page if it’s length is about 1.22 times its width.

Answer 1

X=1.22Y

X x Y = 630.92 inches

Replace X with 1.22Y

Which looks like this

1.22Y x Y = 630.92 inches

Now get Y by itself

Y x Y = 630.92/1.22

Y squared= 630.92/1.22

Y= the square root of 630.92/1.22

Y= 22.74 inches

X= 22.74 x 1.22
X= 27.74 inches

Multiply X and Y to check your answer equals 630.92 inches

Hope this helps

Answer 2

The value of the length of the newspaper is 21.52 inches and the width is 22.74 inches.

What is a rectangle?

The rectangle is a geometrical figure in which opposite sides are equal.

The angle between any two consecutive sides will be 90 degrees.

Area of rectangle = length × width.

Perimeter of rectangle = 2( length + width).

Lets say,

Length of newspaper = l

Width of newspaper = w

Area of newspaper ( rectangle ) = l × w

Now,

Length is about 1.22 times its width.

So,

l = 1.22w

By substituting

1.22w × w = 630.92

1.22w² = 630.92

w² = 517.147

w = 22.74 inches

So,

l = 1.22 × 22.74

l = 21.52 inches

Hence "The value of the length of the newspaper is 21.52 inches and the width is 22.74 inches".

For more about rectangles,

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