Question

when a certain horizontal spring is stretched a distance 10 cm, it exerts a restoring force of magnitude f = 20 n. the work done by a person in stretching this spring from x = 0 to x = 10 cm is

Answer 1

w=f*Dx=20*10=200 J
(not sure)

Answer 2

The Work done by the person in stretching the spring is 1 J

To calculate the work done by the person in stretching the spring, we apply the formula below.

Formula:

• W  = Fe/2............ Equation 1

Where:

• W = Work done
• F = Force
• e = extension

From the question,

Given:

• F = 20 N
• e = 10 cm = 0.1 m

Substitute these values into equation 1

• W = 20(0.1)/2
• W = 1 J.

Hence, The Work done by the person in stretching the spring is 1 J.

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