First you have construct a cycle
heat of solution
Li I (s) --------------------------> Li I (aq)
heat of lattice heat of hydration
Li + I + aq
heat of solution + heat of lattice = heat of hydration
(you take one direction as positive and the other negative)
Therefore,
Heat of solution = heat of hydration - heat of lattice
= -793 + 7.3 * 10^2 = E
For one mole of Lithium iodide E amount of energy is release, then for 10 g how much.
1 = E
10/Molar mass of LiI = x
E * 10/molar mass of LI I = x