Question

What is the mass of 5.26 mol Fe2(SO4)3?
Answer in units of g.

Answer 1

Answer:

2100 g Fe₂(SO₄)₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Stoichiometry

• Using Dimensional Analysis

Atomic Structure

• Reading a Periodic Table

Explanation:

Step 1: Define

5.26 mol Fe₂(SO₄)₃

Step 2: Identify Conversions

Molar Mass of Fe - 55.85 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe₂(SO₄)₃ - 2(55.85) + 3(32.07) + 12(16.00) = 399.91 g/mol

Step 3: Convert

1. Set up:                               $\displaystyle 5.26 \ mol \ Fe_2(SO_4)_3(\frac{399.91 \ g \ Fe_2(SO_4)_3}{1 \ mol \ Fe_2(SO_4)_3})$
2. Multiply/Divide:                 $\displaystyle 2103.53 \ g \ Fe_2(SO_4)_3$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

2103.53 g Fe₂(SO₄)₃ ≈ 2100 g Fe₂(SO₄)₃