Question

A man who is 6 feet tall is flying a kite. The kite string is 75 feet long. If the angle that the kite string makes with the line horizontal to the ground is 35º, how far above the ground is the kite?
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Answer 1

Answer:

49.02 ft

Step-by-step explanation:

See the attached picture for a diagram.

Since the angle is 35 degrees and the only side length we know is the 75 ft long length of the kite (which is the hypotenuse), you would use sin(35) = x/75 where x is the side opposite of the 35 degree angle. Solve for x by doing sin(35) * 75, which equals 43.01823... Make sure you add 6ft from the height of the man. This would make the kite's total height above the ground 49.01823... Round according to the directions you've been given.

Answer 2

Hence , kite flies  49.01 above the ground is the kite

What is angle of elevation?

The angle of elevation is a widely used topic in trigonometry that deals with height and distance. It is defined as the angle formed by the horizontal plane and the oblique line connecting the observer's eye to an object above him. This angle is eventually generated above the surface. The angle of elevation is made in such a way that it is above the observer's eye, as the name implies.

How to solve?

Given angle of elevation is 35degrees

hypotenuse=75 and perpendicular=x

Hence $sin 35^{0}$=$\frac{x}{75}$

$sin 35^{0}*75$=x

49.01=x

Hence , kite flies  49.01 above the ground is the kite

Learn more about  elevation https://brainly.com/question/88158

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