Respuesta :

Answer:

The pressure at Mombasa is 101.396 KPascal.

Explanation:

Given: Reading on barometer = 760 mm

                                                  = 0.76 m

           Density of mercury = 1.36 x [tex]10^{4}[/tex] kg/[tex]m^{3}[/tex]

In this case, the pressure can be expressed as:

P = σhg

Where: σ is the density of mercury, h is height of mercury in the barometer, and g is the acceleration due of gravity.

But, g = 9.81 m/[tex]s^{2}[/tex]

So that,

P = 1.36 x [tex]10^{4}[/tex] x 0.76 x 9.81

  = 101396.16 Pascal

P = 101.395 KPascal

The pressure at Mombasa is 101.396 KPascal.