Question

For C++ ONLY please,
Write a for loop to print all NUM_VALS elements of vector courseGrades, following each element with a space (including the last). Print forwards, then backwards. End with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:
7 9 11 10
10 11 9 7
Hint: Use two for loops. Second loop starts with i-courseGrades.size() - 1 (Notes)
Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector int> courseGrades(4)). See "How to Use zyBooks".
Also note: If the submitted code tries to access an invalid vector element, such as courseGrades at(9) for a 4-element vector, the test may generate strange results. Or the test may crash and report "Program end never reached', in which case the system doesn't print the test case that caused the reported message.
1 #include
2 #include
3 using namespace std; DIIDII
4
5 int maino {
6 const int NUM_VALS - 4;
7 vector int> courseGrades (NUM_VALS);
8 int i;
9
10 for (i = 0; i < courseGrades.size(): ++) {
11 cin >> courseGrades.at(i); /*
12 }
13
14 Your solution goes here */
15
16 return ;
17 }

Answer 1

Answer:

Replace the comment

/*Your solution goes here */

with

for (i = courseGrades.size()-1; i >=0 ; i--) {

cout<<courseGrades.at(i)<<" ";

}

Explanation:

This line iterates through courseGrade in reverse order

for (i = courseGrades.size()-1; i >=0 ; i--) {

This prints each element of courseGrade in reverse followed by blank space

cout<<courseGrades.at(i)<<" ";

}

I added the full program as an attachment