Question

The fan pressure differential gage on an air handler reads 12 cm H2O. What is this pressure differential in kiloPascals

Answer 1

Answer:

$1.18\ \text{kPa}$

Explanation:

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

h = Height of reading = 12 cm

$\rho$ = Density of water = $1000\ \text{kg/m}^3$

Pressure due to height difference is given by

$P=\rho gh\\\Rightarrow P=1000\times 9.81\times 12\times 10^{-2}\\\Rightarrow P=1177.2\ \text{Pa}=1.1772\ \text{kPa}\approx 1.18\ \text{kPa}$

The pressure differential is $1.18\ \text{kPa}$.

Answer 2

The pressure differential will be "1.18 kPa".

According to the question,

• Height of reading, $h = 12 \ cm$
• Density of water, $\rho = 1000 \ kg/m^3$
• Acceleration due to gravity, $g = 9.8 \ m/s^2$

The formula will be:

→ $P = \rho g h$

By putting the values, we get

      $= 1000\times 9.8\times 12\times 10^{-2}$

      $= 1177.2 \ Pa$

      $= 1.18 \ kPa$

Thus the answer above is correct.

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