Answer:
the induced emf in the coil is 15 mV.
Explanation:
Given;
self inductance, L = 1.5 mH = 1.5 x 10⁻³ H
change in current = dI = 1.0 A
change in time, dt = 1/10 = 0.1
The induced emf is calculated as;
[tex]Induced \ EMF = L (\frac{dI}{dt} )\\\\Induced \ EMF = 1.5 \times 10^{-3}\ (\frac{1}{0.1} )\\\\Induced \ EMF = 1.5 \times 10^{-3} \ \times \ 10\\\\Induced \ EMF = 15 \times 10^{-3} \ V\\\\Induced \ EMF = 15 \ mV[/tex]
Therefore, the induced emf in the coil is 15 mV.
