Question

Write the nuclide symbol for Iodine-127. How many protons, electrons, and neutrons are in this isotope of iodine

Answer 1

Answer:

$^{127}_{53} I$

53 protons and electrons and 74 neutrons.

Explanation:

Hello!

In this case, since the nuclide symbol of an isotope is represented by putting the atomic mass as a prefixed superscript and the number of protons as a prefixed subscript, for I-127 we have:

$^{127}_{53} I$

Now we realize this isotope have 53 electrons and protons and the following number of neutrons:

$neutrons= 127-53=74$

Notice this isotope has about the same molar mass of the average iodine atom.

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