Answer:
4.3 g
Explanation:
Ammonium phosphate is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid with ammonia . What mass of ammonium phosphate is produced by the reaction of 2.8 g of phosphoric acid?
Step 1: Write the balanced equation
3 NH₃ + H₃PO₄ ⇒ (NH₄)₃PO₄
Step 2: Calculate the moles corresponding to 2.8 g of H₃PO₄
The molar mass of H₃PO₄ is 97.99 g/mol.
2.8 g × 1 mol/97.99 g = 0.029 mol
Step 3: Calculate the moles of (NH₄)₃PO₄ produced from 0.029 moles of H₃PO₄
The molar ratio of H₃PO₄ to (NH₄)₃PO₄ is 1:1. The moles of (NH₄)₃PO₄ produced are 1/1 × 0.029 mol = 0.029 mol.
Step 4: Calculate the mass corresponding to 0.029 moles of (NH₄)₃PO₄
The molar mass of (NH₄)₃PO₄ is 149.09 g/mol.
0.029 mol × 149.09 g/mol = 4.3 g