Question

On a day when the barometer reads 755 mmhg, a tire pressure gage reads 204 kPa. The absolute pressure in the tire is:

Answer 1

Answer:

2.29mHg

Explanation:

We first do a conversion of gage pressure to mmHg

= 204(10³) / 13595(9.807)

= 204000/133326.165

= 1.53mHg

755 mmhg = 0.755

The pressure is therefore

P = p(atmosphere) + Of

= 1.53 + 0.755

= 2.29 mHg

This is the absolute pressure on this tire. So this answers this question.

Answer 2

The absolute pressure in the tire is equal to 2,285.13 mmHg.

Given the following data:

• Atmospheric pressure of barometer = 755 mmHg.

• Gauge pressure of tire = 204 kPa.

To calculate the absolute pressure in the tire:

First of all, we would convert the value of gauge pressure in kPa to mmHg.

Conversion:

1 kPa = 7.50062 mmHg

204 kPa = $204 \times 7.50062 = 1530.13\;mmHg$

The formula for absolute pressure.

Mathematically, absolute pressure is given by this formula:

$P_{abs} = P_{atm} + P_{ga}$

Where:

• $P_{atm}$ is the atmospheric pressure.

• $P_{ga}$ is the gauge pressure.

Substituting the parameters into the formula, we have;

$P_{abs} = 755 + 1530.13$

Absolute pressure = 2,285.13 mmHg.

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