Question

A drone is flying horizontally when it runs out of power and begins to free fall from 16 m. No drag. If it lands 40 m away (in the x-direction) from where it began to fall, what was its horizontal velocity while it was falling

Answer 1

Answer:

the horizontal velocity while it was falling is 22.1 m/s.

Explanation:

Given;

height of fall, h = 16 m

horizontal distance, x = 40 m

The time to travel 16 m is calculated as;

$t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 16}{9.8} } \\\\t = 1.81 \ s$

The horizontal velocity is calculated as;

$v_x = \frac{X}{t} \\\\v_x = \frac{40}{1.81} \\\\v_x = 22.1 \ m/s$

Therefore, the horizontal velocity while it was falling is 22.1 m/s.

Answer 2

The horizontal velocity while it was falling is

• $22.1m/s$

What is horizontal velocity?

Horizontal velocity becomes important for objects moving in a horizontal direction. Generally, horizontal velocity is horizontal displacement divided by time, such as mph or m/s.

Therefore, from equation of motion

$Time, t = \sqrt\frac{2h}{g}\\\\t = \sqrt\frac{2*16}{9.8}\\\\t = 1.81sec$

Therefore, the horizontal velocity, $V_h$

$V_h = \frac{x}{t}\\\\V_h = \frac{40}{1.81}\\\\V_h = 22.09 or 22.1m/s$

For more information on horizontal velocity, visit

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