A square plate of copper with 50.0-cm sides has no net charge and is placed in a region of a uniform electric field of 80.0 kN/C directed perpendicularly to the plate. Find (a) the charge density of each face of the plate and (b) the total charge on each face.

Respuesta :

Answer:

σ = ±708 nC/m²

Q = ±177 nC

Explanation:

given data

Side of copper plate L = 50 cm

Electric field, E = 80 kN/C

solution

we get here Charge density,σ that is express as

σ = E x ε₀         ....................1

here ε₀ is Permittivity of free space that is 8.85 x 10⁻¹² C²/Nm²

so put value in eq1we get

σ = 80 x 10³ x 8.85 x 10⁻¹²

σ = 708 x 10⁻⁹ C/m²

σ = 708 nC/m²

and

now we get here total change on each faces

Q = σ  A    ...............2

Q = 708 x 10⁻⁹ x (0.50)²

Q = 177 nC

ACCESS MORE