Answer:
σ = ±708 nC/m²
Q = ±177 nC
Explanation:
given data
Side of copper plate L = 50 cm
Electric field, E = 80 kN/C
solution
we get here Charge density,σ that is express as
σ = E x ε₀ ....................1
here ε₀ is Permittivity of free space that is 8.85 x 10⁻¹² C²/Nm²
so put value in eq1we get
σ = 80 x 10³ x 8.85 x 10⁻¹²
σ = 708 x 10⁻⁹ C/m²
σ = 708 nC/m²
and
now we get here total change on each faces
Q = σ A ...............2
Q = 708 x 10⁻⁹ x (0.50)²
Q = 177 nC