Respuesta :

Answer:

0 N/C

Explanation:

Using Gauss' law ∫εE.dA = Q. where E = electric field, dA = differential area and Q = charge enclosed.

Since for r < r₀ where r₀ = radius of the sphere, Q = 0. and ∫εE.dA = ∫εEdAcos180 (since the electric field is directed radially inward opposite to the normal area vector)

∫-εEdA = 0

-εE∫dA = 0

-εEA = 0

E = 0/-εA

E = 0 N/C