Question

Consider a neutron star with a mass equal to the sun, a radius of 10 kmkm, and a rotation period of 1.0 ss. What is the speed of a point on the equator of the star

Answer 1

Answer:

6.28 * 10⁴ m/s

Explanation:

Using the relation :

Given :

Radius, R = 10km

Period, T = 1.0 s

v = (2πR) / T

Where v = velocity of a point

R in meters ;

1km = 1000m = 10³m

10km = 10 * 10³m = 1 * 10^4 m

v = (2π*10^4m) / 1 s

v = 6.2831853 * 10⁴ m/s

v = 6.28 * 10⁴ m/s