Question

What is the mole fraction of ions in solution if the vapor pressure of an aqueous solution of NaCl is 2.02 kPa

Answer 1

Answer:

.133

Explanation:

Dissolution of solute lowers the vapor pressure of solvent .

Relative lowering by non -volatile solute is equal to mole fraction of solute dissolved .

Vapor pressure of pure water is 2.33 k Pa

Lowering of vapor pressure = 2.33 - 2.02 = .31 k Pa .

relative lowering = .31 / 2.33 = .133

relative lowering will be equal to mole fraction of non volatile solute like NaCl

so mole fraction of NaCl dissolved = .133