Question

A loop should output 1 to n. If n is 5, the output is 12345. What should XXX and YYY be? Choices are in the form XXX / YYY. cin >> n; for (XXX; i++) { cout << YYY; }

Answer 1

Answer:

$i = 0; i < n / i + 1$

Explanation:

Given that:

a loop output 1 → n

if n = 5

output = 12345

n = scnr.nextInt();

for $(XXX; i++)$

{

System.out.printIn(YYY);

}

XXX / YYY is $i = 0; i < n / i + 1$