A 9800 N car traveling at 22 m/s strikes a concrete bridge support and comes to a complete halt in 0.5 sec. Calculate the impulse of the force.

Respuesta :

Answer:

21977.56kg⋅m/s

Explanation:

Step one:

Given data

Weight of car= 9800N

The mass of the car is

m= w/g

m= 9800/9.81

m=998.98kg

Velocity of car= 22 m/s

time of impact= 0.5 seconds

Required

The impulse of the force F

Step two:

Ft= mv

Ft= 998.98*22

Ft=21977.56kg⋅m/s

The impulse is 21977.56kg⋅m/s

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