Answer:
0.074M is concentration of the HNO₃ solution
Explanation:
The reaction of neutralization of nitric acid, HNO₃ with NaOH is:
HNO₃ + NaOH → H₂O + NaNO₃
Where 1 mole of nitric acid reacts per mole of NaOH
Based on the chemical reaction, the moles of NaOH at equivalence point are equal to moles of HNO₃ presents in the solution. With the moles and the volume we can find molarity as follows:
Moles NaOH = Moles HNO₃:
0.14L * (0.2mol NaOH / L) = 0.028mol NaOH = 0.028mol HNO₃
Molarity:
0.028mol HNO₃ / 0.38L =
0.074M is concentration of the HNO₃ solution
