Question

An object on a number line moved from x = 12 m to x = 124 m and
moved back to x = 98 m. The time interval for all the motion was 10 S.
What was the average velocity of the object?

Answer 1

answer: 12.6 m/s

distance between 12m and 124m is 112

distance between 112 and 98 is 14.

Add 14 to 112 for total distance. Total distance travelled is 126 meters

divide distance by time to get average velocity: 126/10 = 12.6

Answer 2

The average velocity of the object was 13.8 m/s.

Average velocity is defined as total displacement divided by the total time i.e

$Average Velocity = \frac{Total Displacement }{Total Time}$

To solve the question given above, we'll begin by calculating the total displacement of the object. This can be obtained as follow:

Displacement from x = 12 m to x = 124 m is given by = 124 – 12 = 112 m

Displacement from x = 124 m to x = 98 m is given by = 124 – 98 = 26 m

Total displacement = 112 + 26 = 138 m

Finally, we shall determine the average velocity. This can be obtained as follow:

Total displacement = 138 m

Total time = 10 s

Average velocity =?

$Average velocity = \frac{Total Displacement }{Total Time}\\\\Average velocity = \frac{138}{10}$

Average velocity = 13.8 m/s

Therefore, the average velocity of the object was 13.8 m/s.

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