Question

An iron bolt is used to connect two iron plates together. the bolt must withstand shear forces up to about 3000 n. calculate the minimum diameter for the bolt, based on a safety factor of 6.3.

Answer 1

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Shear strength of steel 
= 0.75 * 800 * 10^6 N/m2 

total load with safety factor 
= 3000 * 5.6 
= 16800 N 

Cross section area needed 
= 16800 / 0.75 * 800 * 10^6 

= 28 * 10^(-6) m2 

Diameter of bolt 
= square root of [ 4 * area / phi} 

= sq root [ 35.65 10^ -6] 

= 5.97 * 10^ -3 m 

= 5.97 mm