If a 50 kg student is pushed in a rolling chair with a force of 20 N, what is the student’s acceleration?
2.5 m/s2
4 m/s2
1,000 m/s2
0.4 m/s2

Respuesta :

Answer:

0.4m/s²

Explanation:

Given parameters:

Mass of student = 50kg

Force  = 20N

Unknown:

Acceleration = ?

Solution:

From Newton's second law of motion,

          Force  = mass x acceleration

   Acceleration  = [tex]\frac{Force }{mass}[/tex]   = [tex]\frac{20}{50}[/tex]    = 0.4m/s²