Question

HELP
A movie theater is arranged with 7 seats in the front row, 12 seats in the middle row, and 11 seats in the back row. People enter the movie theater and randomly sits in different spots. What is the probability that the first person who enters the theater will be in the middle row?


type in your fraction answers as a/b

Answer 1

Answer:$P=\frac{2}{5}$

Step-by-step explanation:

Given

A movie theater has 7 seats in the front row  

12 seats in the middle row

11 seats in the back row

Probability first person who enters the theater will be in the middle row

$P=\frac{\text{No. of middle seats}}{\text{total seats}}$

$P=\frac{12}{7+12+11}=\frac{12}{30}$

$P=\frac{2}{5}$