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Answer:

[tex]80[/tex]° and [tex]10[/tex]°

Step-by-step explanation:

Complementary angles are a pair of angles whose measures have a sum of [tex]90[/tex]°. Therefore, if we let the measure of the bigger angle be [tex]x[/tex], then the measure of the smaller angle will be [tex]x-70[/tex] because we are given that the difference of the measures of the two angles is [tex]70[/tex]°. We can write the following equation to solve for [tex]x[/tex]:

[tex]x+x-70=90[/tex]

Solving for [tex]x[/tex], we get:

[tex]x+x-70=90[/tex]

[tex]2x-70=90[/tex] (Simplify LHS)

[tex]2x-70+70=90+70[/tex] (Add [tex]70[/tex] to both sides of the equation to isolate [tex]x[/tex])

[tex]2x=160[/tex] (Simplify)

[tex]\frac{2x}{2}=\frac{160}{2}[/tex] (Divide both sides of the equation by [tex]2[/tex] to get rid of [tex]x[/tex]'s coefficient)

[tex]x=80[/tex] (Simplify)

Therefore, the measure of one angle is [tex]80[/tex]° and the measure of the other angle is [tex]x-70=80-70=10[/tex]°. Hope this helps!

We know, sum of complementary angles = 90°

Let, one of the angle = x°

∴ Another angle = (90 - x)°

As per condition,

(x°) - (90 - x)° = 70°

⇒ x° - 90° + x° = 70°

⇒ 2x° = 70° + 90° = 160°

⇒ x° = 80°.

So, angles are:-

  1. x° = 80°
  2. (90 - x)° = (90 - 80)° = 10°.
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