nixiedancer41 nixiedancer41
  • 21-01-2021
  • Mathematics
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How do you evaluate tanθ if secθ = -7/3 and θ terminates in QII?

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ChoiSungHyun
ChoiSungHyun ChoiSungHyun
  • 21-01-2021

Step-by-step explanation:

In Quadrant II, tanθ is negative.

We have tan²θ + 1 = sec²θ.

=> tanθ = - √(sec²θ - 1)

= -√[(-7/3)² - 1]

= -√(40/9)

= -√40/3

= -2√10/3.

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