Question

$(-3x^2y)^{4}$


PLEASE EXPLAIN HOW YOU GOT YOUR ANSWER

Answer 1

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

so

$-3x^{2*4} y^{1*4}$

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well  and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression

$81x^{8}y^{4}$

Answer 2

When you have an power outside of a bracket, you have to multiply all the powers inside by the one outside...

So you would get x^2 x ^4 which is x^8

And y x ^4 which would be y^4

Therefore the answer will be -3x^8y^4

Hope this helps! Any questions let me know :)