Question

On a coordinate plane, a point is at (negative 4, negative 4) and (negative 4, negative 10).
What is the distance between (–4, –10) and (–4, –4)?
3 units
4 units
6 units
8 units

Answer 1

Answer:

Option C.

Step-by-step explanation:

Hey there!

The points are; (-4,-4) and (-4,-10).

Use distance formula.

$d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

~ Put all values.

$d = \sqrt{ {( - 4 + 4)}^{2} + ( { - 10 + 4)}^{2} }$

~ Simplify it.

$d = \sqrt{ {0}^{2} + ( { - 6)}^{2} }$

$d = \sqrt{36}$

Therefore, distance between the points is 6 units.

Hope it helps...

Answer 2

Answer:

Option: C (6)

Step-by-step explanation: