Answer:
a) The initial momentum of the ball is 22.5 kg·m/s
b) The magnitude of the momentum imparted by the ball is 30 kg·m/s
Explanation:
The question is based on change in momentum
The mass of the ball, m = 0.75 kg
The velocity with which the ball is thrown against the wall, u = 30 m/s
The time duration it takes while the ball is in contact with the wall, Δt = 0.05 sec
The velocity of the ball as it bounce back, v = -10 m/s (The ball moves in the opposite direction)
a) The initial momentum of the ball, [tex]P_{Initial}[/tex] = m × u = 0.75 kg × 30 m/s = 22.5 kg·m/s
b) The final momentum of the ball, [tex]P_{Final}[/tex] = m × v = 0.75 kg × (-10 m/s) = -7.5 kg·m/s
The momentum imparted by the ball, ΔP = The final momentum - The initial momentum
∴ ΔP = [tex]P_{Final}[/tex] - [tex]P_{Initial}[/tex] = -7.5 kg·m/s - 22.5 kg·m/s = -30 kg·m/s
The magnitude of the momentum imparted by the ball, [tex]\left | \Delta P \right |[/tex] = 30 kg·m/s
