Question

The second side of a triangle is 8 inches less in the first side side side is 14 inches more than the first side the perimeter of the triangle 63 inches find each side of a triangle

Answer 1

b = c+8 --> c = b-8
a = b + 14
P = 63

a + b + c = 63
b+14 + b + b - 8 = 63
3b = 63 - 14 + 8
3b = 71 - 14
3b = 57
b = 57/3
b = 19
a = b+14
a = 19+14
a = 33
c = b-8
c = 19-8
c = 11