Respuesta :

Answer:

The value of f(1)=31

Step-by-step explanation:

Given: [tex]f(n+1)=f(n)-3[/tex]

f(4)=22

We need to find the f(1)

Put n=3 into recursion formula

[tex]f(3+1)=f(3)-3[/tex]

[tex]f(3)=22+3=25[/tex]

Put n=2 into recursion formula

[tex]f(2+1)=f(2)-3[/tex]

[tex]f(2)=25+3=28[/tex]

Put n=1 into recursion formula

[tex]f(1+1)=f(1)-3[/tex]

[tex]f(1)=28+3=31[/tex]

Hence, The value of f(1)=31

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