Answer:
The value of f(1)=31
Step-by-step explanation:
Given: [tex]f(n+1)=f(n)-3[/tex]
f(4)=22
We need to find the f(1)
Put n=3 into recursion formula
[tex]f(3+1)=f(3)-3[/tex]
[tex]f(3)=22+3=25[/tex]
Put n=2 into recursion formula
[tex]f(2+1)=f(2)-3[/tex]
[tex]f(2)=25+3=28[/tex]
Put n=1 into recursion formula
[tex]f(1+1)=f(1)-3[/tex]
[tex]f(1)=28+3=31[/tex]
Hence, The value of f(1)=31