contestada

A 1400 kg car has an engine that exerts 9800 N of force. If the force of friction between the car and the road is roughly 2801 N, what is the car's acceleration?

Respuesta :

Friction opposes the force provided by the car's engine, so by Newton's second law the acceleration a is such that

F = 9800 N - 2801 N = (1400 kg) a

a = (6999 N) / (1400 kg) ≈ 5.0 m/s²

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