Respuesta :
Applying the logarithmic function, it is found that:
- A fossil with 47% of its carbon-14 remaining is approximately 2997 years old.
- A fossil that is 7,000 years old will have approximately 56.71% of its carbon-14 remaining.
The age of a fossil with a proportion c of carbon 14 remaining is given by:
[tex]t(c) = -3970\ln{c}[/tex]
If the fossil has 47% of carbon-14 remaining, we have that [tex]c = 0.47[/tex], and thus:
[tex]t(0.47) = -3970\ln{0.47} = 2997[/tex]
For a fossil that is 7000 years old, we have that [tex]t(c) = 7000[/tex], and hence:
[tex]t(c) = -3970\ln{c}[/tex]
[tex]\ln{c} = -\frac{3970}{7000}[/tex]
[tex]e^{\ln{c}} = e^{-\frac{3970}{7000}}[/tex]
[tex]c = 0.5671[/tex]
A fossil that is 7,000 years old will have approximately 56.71% of its carbon-14 remaining.
A similar problem is given at https://brainly.com/question/23120675