Respuesta :
I'm sorry, when I answered this I'm pretty sure I wasn't in algebra two yet. The correct answer is 4/52 * 3/51 = 1/221
Answer:
Option C. 1/221
Step-by-step explanation:
Total cards in a standard deck of cards = 52
Number of ace in a deck of cards = 4
So probability to draw an ace [tex]P_{1}=\frac{4}{52}[/tex]
Since the cards were drawn without replacement means remaining cards in deck of cards now = 51
Number of aces remaining = 3
So probability of drawing another ace [tex]P_{2}=\frac{3}{51}[/tex]
Now probability to draw both the aces
= [tex]P_{1}\times P_{2}[/tex]
[tex]\frac{4}{52}\times \frac{3}{51}=\frac{1}{13}\times \frac{1}{17}[/tex]
= [tex]\frac{1}{221}[/tex]
Option C. is the answer.