Answer:
12556.8Nm
Explanation:
A 4 m long, 500 kg steel beam extends horizontally from the point where it is bolted to the frame of a building. A 70 kg man stands on the far end of the beam. What is the magnitude of the torque at the point where the beam attaches to the building
Step one:
Given data
Length of steel x =4m
Mass of steel m1=500kg
Mass of man m2=70kg
The center of the mass of the steel is from the center
Cm=x/2
Cm=4/2= 2m
Torque =force*perpendicular distance
Force =mg
The total torque =torque due to weight of steel +torque due to the man's weight
Total torque = 500*9.81*2+70*9.81*4
Total torque =9810+2746.8
Total torque =12556.8Nm
