Answer:
The 49th term of the given sequence
t₄₉ = 28
Step-by-step explanation:
Step(i):-
Given sequence 460, 451,442,....
first term a = 460
The difference of two terms of given sequence
d = 451 -460 = -9
d = 442 -451 = -9
and so on
The given sequence is in arthematic progression(A.P)
Step(ii):-
The [tex]n^{th}[/tex] of the given sequence
[tex]t_{n} = a + ( n-1 ) d[/tex]
n = 49 , a = 460 and d = -9
The 49th term
[tex]t_{49} = 460 + ( 49-1 ) (-9)[/tex]
[tex]t_{49} = 460 + ( 49-1 ) (-9) = 460 -432 = 28[/tex]
Final answer:-
The 49th term of the given sequence
t₄₉ = 28