Respuesta :

Moles of gas : 0.414

Further explanation

Given

V =29.90 liters,

P = 336.99 mmHg = 0,443 atm

T = 390K

Required

moles

Solution

In general, the gas equation can be written  

[tex]\large {\boxed {\bold {PV = nRT}}}[/tex]

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)

T = temperature, Kelvin  

Input the equation

n = PV/RT

n = 0.443.29.9/0.082.390

n= 0.414 moles

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