Answer:3.33 m/s
Explanation:
Given
mass of Putty M=2 kg
the velocity of bob u=5 m/s
mass of doll m=1 kg
As there is no external force acting so linear momentum is conserved
Mu=(M+m)v
where v=common velocity of putty and doll after the impact
[tex]2\times 5=(2+1)v\\v=\dfrac{10}{3}\ m/s\approx3.33\ m/s[/tex]