Given :
Two charges q1 and q2 exert a force of 20 N on each other.
To Find :
If the charge of q1 is doubled, what will the new force be?
1) 40 N 2) 80 N 3) 20 N 4) 10 N
Solution :
We know, electrostatic force between two charges is given by :
[tex]F = \dfrac{kq_1q_2}{r^2}[/tex]
Here, F = 20 N.
[tex]20 = \dfrac{kq_1q_2}{r^2}[/tex]
Now, if [tex]q_1[/tex] is doubled :
[tex]F'= \dfrac{k(2q_1)q_2}{r^2}\\\\F'= 2\dfrac{kq_1q_2}{r^2}\\\\F'= 2\times F\\\\ F'= 2\times 20 \ N\\\\F'= 40 \ N[/tex]
Therefore, if the charge of q1 is doubled, new force will be 40 N.