Answer:
the centripetal acceleration of the puck is 27 m/s²
Explanation:
Given;
radius of the circular path, r = 3.0 m
velocity of the puck in the circular motion, v = 9.0 m/s
The centripetal acceleration of the puck is calculated as;
[tex]a_c = \frac{v^2}{r} \\\\a_c = \frac{(9)^2}{3} \\\\a_c = 27 \ m/s^2[/tex]
Therefore, the centripetal acceleration of the puck is 27 m/s²