Question

A sample of 200 college freshmen was asked how many hours per week they spent playing video games. The following frequency distribution presents the results. Number of Hours Frequency 21 37 1.0-7.9 8.0-14.9 15.0-21.9 22.0-28.9 29.0-35.9 36.0-42.9 43.0-49.9 50.0-56.9 57.0-63.9 64.0-70.9
Part 1 of 2
The class width is 7
Part 2 of 2
(a) What percentage of students play video games for less than 50 hr per week? % of the students play video games for less than 50 hr per week.
(b) What percentage of students play video games for 43 or more hours per week? % of the students play video games for 43 or more hours per week

Answer 1

Answer:

$\% Below\ 50 = 88 \%$

$\% 43\ or\ more = 17 \%$

Step-by-step explanation:

Given

$Total = 200$

The attachment presents the table properly

Solving (a): Percentage of those who play for less than 50 hours weekly

To do this, we simply consider the frequency of students that fall within:

1.0 - 7.9, 8.0 - 14.9,......,43.0 - 49.9

Their frequency is:

$Frequency = 21 + 37 + 40 + 27 + 23 + 18 + 10$

$Frequency = 176$

The percentage is then calculated as:

$\% Below\ 50 = \frac{Frequency}{Total} * 100\%$

$\% Below\ 50 = \frac{176}{200} * 100\%$

$\% Below\ 50 = \frac{176* 100}{200} \%$

$\% Below\ 50 = \frac{176* 1}{2} \%$

$\% Below\ 50 = \frac{176}{2} \%$

$\% Below\ 50 = 88 \%$

Solving (b): Percentage of those who play for 43 or more hours weekly

To do this, we simply consider the frequency of students that fall within:

43.0 - 49.9,......,64.0 - 70.9

Their frequency is:

$Frequency = 10 + 7 + 5+12$

$Frequency = 34$

The percentage is then calculated as:

$\% 43\ or\ more = \frac{Frequency}{Total} * 100\%$

$\% 43\ or\ more = \frac{34}{200} * 100\%$

$\% 43\ or\ more = \frac{34* 100}{200} \%$

$\% 43\ or\ more = \frac{34* 1}{2} \%$

$\% 43\ or\ more = \frac{34}{2} \%$

$\% 43\ or\ more = 17 \%$

Answer 2

Using the percentage concept, it is found that:

a) 88% of the students play video games for less than 50 hr per week.

b) 21.5% of the students play video games for 43 or more hours per week.

What is a percentage?

• The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

$P = \frac{a}{b} \times 100\%$

Item a:

• Researching the problem on the internet, it is found that there is a total of 21 + 37 + 40 + 27 + 23 + 18 + 10 + 7 + 5 + 12 = 200 students.

• Of those, 21 + 37 + 40 + 27 + 23 + 18 + 10 = 176 played for less than 50 hours per week, hence:

$P = \frac{176}{200} \times 100\% = 88\%$

88% of the students play video games for less than 50 hr per week.

Item b:

10 + 7 + 5 + 12 = 34 play for 43 or more hours, hence:

$P = \frac{43}{200} \times 100\% = 21.5\%$

21.5% of the students play video games for 43 or more hours per week.

You can learn more about the percentage concept at https://brainly.com/question/10491646