Given :
Two cylinders contain pistons that are connected by fluid in a hydraulic system.
A force of 1,300 N is exerted on one piston with an area of 0.05 m².
To Find :
The force exerted on the other piston that has an area of 0.08 m.
Solution :
Since, force is exerted between two cylinder, it means pressure is constant.
So,
[tex]P_1 = P_2\\\\\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}\\\\\dfrac{1300\ N}{0.05 \ m^2} = \dfrac{F_2}{0.08\ m^2}\\\\F_2 = \dfrac{1300\times 0.08}{0.05}\ N\\\\F_2 = 2080\ N[/tex]
Hence, this is the required solution.
